МТИСШ -ын давтлага - е-Самбарын бичээс №16

4200 r --- 60 sec
  1         x
x = 60/4200 = 1*1000/70 =14.2


search time of A is 7.1 millsec


1000 millsec == 20* 1000 kB
  X             100kB
  x = 1000*100kB/20* 1000 kB = 5 millsec


Access = 12 msec + 5.5 + 3.3 = 
20.8 millsec - (14 + 7.1+ 5) =
5.3


2*[0.4 * (CacheSearchTime+CacheReadBlock)]+
0.6 * ( 17 millsec) 


0.4 * 1.4 + 0.6*17 = 0.56 + 10.2 = 10.76 + 1.4


1  
1 + 1
2   


2 * 0.56 + 10.2 = 11.32


0,0011,1111,1100


0,1000,0000,0000   2048

Ч. Эрдэнэбат

2011-10-24